The UK's Finest Independent Forum for Shooters and Gun Owners. Est 2010.

Posted: **Mon Feb 28, 2011 9:23 pm**

Which is correct?

The number of equally-sized lead balls making up 1 Lb in weight which can fit in the barrel = bore/gauge.

OR

The weight of a solid sphere of lead that will fit the bore of the firearm, and is expressed as the multiplicative inverse of the sphere's weight as a fraction of a pound (e.g., a 1/12th pound ball fits a 12-gauge bore).

No Googling!!!

:roll:

Posted: **Mon Feb 28, 2011 9:26 pm**

the second was always my understanding :shock:

Alan

Posted: **Mon Feb 28, 2011 9:33 pm**

HMMMMM...

Any more for any more?

:evil: :evil: :lol: :lol: :lol:

Posted: **Mon Feb 28, 2011 9:48 pm**

The latter, possibly, maybe, perhaps?

Yes - I think!

:roll:

Posted: **Mon Feb 28, 2011 9:57 pm**

Second is my understanding as well

Posted: **Mon Feb 28, 2011 9:58 pm**

Whats the difference 'tween the options?

Posted: **Mon Feb 28, 2011 10:06 pm**

I thought the first one was correct?

Posted: **Mon Feb 28, 2011 11:03 pm**

Is the first one incorrect?

Have I got Dromia guessing?

:evil: :lol: :lol:

Posted: **Tue Mar 01, 2011 3:31 am**

Both, if my grasp of English has not left me completely.

Robin, do I have this much time to look forward to when I retire. Can't wait!!!!!!

Posted: **Tue Mar 01, 2011 6:28 am**

When I got my first musket I was told it was the first one.

The UK's Finest Independent Forum for Shooters and Gun Owners. Est 2010.

Define Guage

Define Guage

Re: Define Guage

Re: Define Guage

Re: Define Guage

Re: Define Guage

Re: Define Guage

Re: Define Guage

Re: Define Guage

Re: Define Guage

Re: Define Guage