Define Guage
Posted: Mon Feb 28, 2011 9:23 pm
Which is correct?
The number of equally-sized lead balls making up 1 Lb in weight which can fit in the barrel = bore/gauge.
OR
The weight of a solid sphere of lead that will fit the bore of the firearm, and is expressed as the multiplicative inverse of the sphere's weight as a fraction of a pound (e.g., a 1/12th pound ball fits a 12-gauge bore).
No Googling!!!
:roll:
The number of equally-sized lead balls making up 1 Lb in weight which can fit in the barrel = bore/gauge.
OR
The weight of a solid sphere of lead that will fit the bore of the firearm, and is expressed as the multiplicative inverse of the sphere's weight as a fraction of a pound (e.g., a 1/12th pound ball fits a 12-gauge bore).
No Googling!!!
:roll: